mg is mass*acceleration due to gravity.
Something is gravely wrong here? You must be lacking a text, or class instruction. mu (or the greek symbol for mu) is pretty standard. mg is pretty standard for weight.
Please help me with these three questions,they deal with coefficient of friction
1) A car rounds a turn of radius 25m at a speed of 20m/s. Find the coefficient of friction neccessary to keep the car on the road
2) A man is attempting to slide a piece of furniture weighing 750N long a floor. Ifhe exerts a force of 75N along a rope and angle of 35 degrees and the object does not move, what is the minimum value for te coeficient of friction?
3) Consider a block on a plane inclined at an angle of 30 degres. If the block weights 950N, what coefficient of friction is neccessary to hold it stationary?
Physics - bobpursley, Wednesday, January 27, 2010 at 8:00pm
1) set mv^2/r= mu*mg
solve for mu
2) the vertical component of tension reduces weight.
friciton= mu*(mg-75sin35)
horizontalforce= 75*cos35
set them equal, solve for mu.
3) I will be happy to critiqeu your thinking.
I wanted to know what you mean by the formulas. I do not know what the mg stands for...If it is miligrams then how does that relate to the problem. Thanks for your time again.
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