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Please help me with the following question:

Consider the following ion; XF2-2
What is the oxidation number assigned to element “X”? Show your work

I'm having trouble writing the steps.

2 answers

Just follow the rules.
F is -1; there are two of them to make -2. The XF2^2- ion must be left with a charge of -2.
X + 2F = -2
X + 2(-1) = -2
X -2 = -2
X = -2+2 = 0
X must have an oxidation state of zero.
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