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I = (1/6) m L^2
Torque = I * angular acceleration
24 = (1/6) m L^2 * 6.25^2
but L = 1.2
so
24 = (1/6) m (1.2*6.25)^2
Please help me understand with steps, I really don't get it
A square plate has a side length of 1.20 m. A 24.0-N ~ m torque is applied about an axis perpendicular to the plate through its center. If it experiences an angular acceleration of 6.25 rad/s2, calculate the mass of the plate.
1 answer
1 answer