√6+2 + √6-2 = 2√6
(√6+2)(√6-2) = 6-2^2 = 2
Now do the math
Please help me to solve this Radical Expressions and equations word problem.
Here is the question:
Find the perimeter and the area of the rectangle.
Here are the measurements: length is (sqrt 6+2) and the width is (sqrt 6-2)
1 answer