#1. Do it as usual, but you will be solving for 1/x and 1/y.
D = -1
Dx = -2
Dy = -3
So, 1/x = Dx/D = 2, 1/y = Dy/D = 3
x = 1/2, y = 1/3
Same thing, but you are solving for logx and logy:
D = -5
Dx = -14
Dy = -3
logx = 14/5
logy = 3/5
x and y depend on the base of the logs.
Please, help me to solve this problems by Cramer rule
Question number :
1. 5/x + 3/y = 19
2/x + 1/y = 7
Question number :
2. log x + 2 log y = 4
2 log x - 3 log y = 1
so confuse..
1 answer