Question

please help me to find the least possible consecutive odd integers such as that eight times the smaller one is at least 25 more than the difference of the two integers. I don't remember my teacher teaching this so please help me.

Answer 1

8n>n+2-n+25
n>27/8
so the smallest odd integer is 5, the next 7
check:
8*5>7-5+25
40>27 checks.

Answer 2

the two numbers are x and x+2. So, you know that
8x >= 25+2
8x >= 27
x >= 27/8 = 3.375
so, you need x >= 4
But x is odd, so x=5
8*5 = 40 >= 27
The previous odd integer is 3, and 8*3 < 27