please help me simplify
(x^3+8)/(x^4-16).
thanks.
The denominator is cleary the differerence of two squares (X^2-4)(x^2+4). That can again be factored to (x+2)(x-2)(x^2+4).
The numerator can be factored using the trinomial simplification..
http://www.algebra-online.com/sum-difference-cubes-1.htm
so (x^2-2x+4)/((x-2)(x^2+4)) is as far as I can go?
yes.
not true