Asked by rob
please help me simplify
this exponent 24^-1a^-3/6^-2b^-2
Basically it's this right?:
(24^-1 * a^-3) / (6^-2 * b^-2)
so:
(1/24 * 1/(a^3)) / (1/(6^2) * 1/(b^2))
you should know that 6^2 = 36 so 1/(6^2) = 1/36
Now multiply:
(1/(24a^3)) / (1/(36b^2))
Then flip:
(24a^3) / (36b^2)
A helpful hint when dividing fractions:
(A/B) / (C/D) =
Think that the "inside" (a.k.a., the numbers closest to the division line) will be multiplied to create the numerator, while the "outside" will be the denominator.
= (B*C)/(A*D)
woops. i flipped that...SORRY! it becomes AD / BC
so, inside = denominator, outside = numerator
(A/B)/(C/D) =
(A/B)*(D/C) = (A*D)/(B*C)
this exponent 24^-1a^-3/6^-2b^-2
Basically it's this right?:
(24^-1 * a^-3) / (6^-2 * b^-2)
so:
(1/24 * 1/(a^3)) / (1/(6^2) * 1/(b^2))
you should know that 6^2 = 36 so 1/(6^2) = 1/36
Now multiply:
(1/(24a^3)) / (1/(36b^2))
Then flip:
(24a^3) / (36b^2)
A helpful hint when dividing fractions:
(A/B) / (C/D) =
Think that the "inside" (a.k.a., the numbers closest to the division line) will be multiplied to create the numerator, while the "outside" will be the denominator.
= (B*C)/(A*D)
woops. i flipped that...SORRY! it becomes AD / BC
so, inside = denominator, outside = numerator
(A/B)/(C/D) =
(A/B)*(D/C) = (A*D)/(B*C)
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