Please help me out! Gas law homework!

How many liters of HCl (g) at STP can be produced from 5.44 g of Cl2 and excess H2 according to the following equation?

H2 (g) + Cl2 (g) --> 2 HCl (g)

Thank you so much in advance.

1 answer

mols Cl2 = 5.44/molar mass Cl2.
L Cl2 = mols x 22.4 L = ?
L HCl = L Cl2 x (2 mol HCl/1 mol Cl2) = L Cl2 x 2 = ?