Please help me!! I need this as soon as possible.

Question

2.A billiard ball at rest is struck by the cue ball of the same mass whose speed is 5 m/s .After an elastic collision the cue ball goes off at 50 degree with respect to its original direction of motion and the struck ball goes off at 40 degree with respect to this direction,What are the final speed of the balls?Illustrate the situation given

Answer 1

v1fcos40+v2fcos50=5
v1fsin40 = v2fsin50
solve 2nd eq for v1f or vsf and plug into eq 1

Answer 2

I what an anwer

Answer 3

Final answer:
v1 = 3.83 m/s
v2 = 3.21 m/s