Please help me I have no idea how to do this problem at all.

Question

Question:A sledge loaded with bricks has a total mass of 17.8 kg and is pulled at constant speed by a rope inclined at 20.8° above the horizontal. The sledge moves a distance of 20.6 m on a horizontal surface. The coefficient of kinetic friction between the sledge and surface is 0.500.
(a) What is the tension in the rope?_ N

(b) How much work is done by the rope on the sledge?__ kJ

(c) What is the mechanical energy lost due to friction?__KJ

Answer 1

you start by breaking up the tension in the rope into a vertical part (which reduces force normal and friction), and a horizontal part.
Forcenormal=mg-vertical component of tension
Friction=forcenormal*mu
so to move, the horizontal component of tension must at least equal fricion.

You can now find tension from that.
work on sled? tensioninhorizontal*distance.
frictionwork? friction*distance