heat=mc deltaT
deltaT=74.0/(500*2.46)= ?
now final temp, equals initial temp 25C + deltatemp
Please help me! I do not know what to do.
500.0 g ethyl alcohol at 25°C (C = 2.46 J/g x °C) absorbs 74.0 J of heat energy. What is the final temperature?
What is the specific heat constant if 621 g of Metal A raises the temperature of 500.0 g of water by 3.20°C and the temperature of the metal decreases by 42.5°C.
2 answers
For part B
heat lost by metal + heat gained by water = 0
[mass metal x sp.h. metal x 43.5] + [mass H2O x sp.h water x 3.20] = 0
Solve for sp.h. (specific heat) metal
heat lost by metal + heat gained by water = 0
[mass metal x sp.h. metal x 43.5] + [mass H2O x sp.h water x 3.20] = 0
Solve for sp.h. (specific heat) metal
2 answers