Please help me, I am in dire need of it,

Question

A football quarterback shows off his skill by throwing a pass {5.70 m downfield and into a bucket. The quarterback consis- tently launches the ball at 38.00' above horizontal, and the bucket is placed at the same level from which the ball is thrown. What initial speed is needed so that the ball lands in the bucket? By how much would the launch speed have to be increased if the bucket is moved to 46.50 m downfield?

Answer 1

the time is the same for vertical and horizontal travel

V ... t = 5.7 / [s cos(38)]

H ... t = 2 [s sin(38)] / g

solve for s (speed)

change 5.7 to 46.5 to find the launch speed for the longer throw

Answer 2

Thank you so much Scott, I've been trying to figure out this problem for the longest.

Answer 3

So I did 5.7cos(38)= 4.49, 2sin(38)= 1.23 and 46.50 cos(38)=36.64 did I do this correctly and what shall I do next?

Answer 4

a. Range = Vo^2*sin(2A)/g = 5.70 m.
Vo^2*sin(76)/9.8 = 5.7
Vo^2*0.099 = 5.7
Vo^2 = 57.57
Vo = 7.59 m/s.

b. Vo^2*sin(76)/9.8 = 46.5.
Vo = ?.