This looks like a "prime" quadratic. With trial and error trying:
(-4t )(t )
or
(-2t )(t )
you cannot get it to work. So there are no "interger" solutions. You can use the famous "quadratic equation" to get an approximation. ARe you familiar with this?
please help me do this..im having so much trouble ...i need to solve this problem in quadratic formula...
-4t^2-9t-3=0
thank you so much for helping..if u can do this and help me then i can do the rest of my homework....i hope..lol
5 answers
this is a quadratic formula...i need to solve it using the quadratic formula!!
ok. I assume you know the quadratic formula. It is hard to write it here. In your example, a = -4, b = -9 and c = -3. So, when you plug these in, you end up with (9+sqrt43)/8 and
(9-sqrt43)/8
this is approx: 15.56/8 and 2.44/8. These are your 2 solutions.
(9-sqrt43)/8
this is approx: 15.56/8 and 2.44/8. These are your 2 solutions.
woops...slight mistake.
It's actually: (9+sqrt33)/8 and
(9-sqrt33)/8
or 14.74/8 and 3.26/8.
It's actually: (9+sqrt33)/8 and
(9-sqrt33)/8
or 14.74/8 and 3.26/8.
-b = 9 all right
but 2a = -8
so
-b/2a = -9/8 not +
but 2a = -8
so
-b/2a = -9/8 not +