I would use substitution
from the 2nd: y = 3 - 9x
sub into the 1st
3-9x = 25x^2 + x
25x^2 + 10x - 3 = 0
(5x-1)(5x+3) = 0
x = 1/5 or x = -3/5
if x = 1/5 , y = 3-9(1/5) = 6/5
if x = -3/5 , y = 3 - 9(-3/5) = 42/5
PLEASE HELP ME ASAP!!!!!!!!!!!! :) I really need to remember on how to do this equation.
Solve the system algebraically.
y=25x^2+x
9x+y=3
2 answers
Thank you so much I really appreciate it.