please help im really struggling
Point A is located at (2, 6) and point B is located at (18, 12).
What point partitions the directed line segment AB¯¯¯¯¯ into a 2:3 ratio?
6 answers
i know that this deals with the midpoint formula and stuff like that
the x distance is ... 18 - 2 = 16
2/5 * 16 = 32/5 = 6.4
Ax + 6.4 = 8.4
the y distance is ... 12 - 6 = 6
2/5 * 6 = 12/5 = 2.4
Ay + 2.4 = 8.4
partition point ... (8.4,8.4)
2/5 * 16 = 32/5 = 6.4
Ax + 6.4 = 8.4
the y distance is ... 12 - 6 = 6
2/5 * 6 = 12/5 = 2.4
Ay + 2.4 = 8.4
partition point ... (8.4,8.4)
THANK YOU !
let the point be P(x,y)
you don't say if AP : PB = 2 : 3 or 3 : 2
I will assume the first. If otherwise it is very easy to change
If you make a sketch and draw the right-angled triangles, you can see ....
for the x:
(x-2)/(18-x) = 2/3
3x - 6 = 36 - 2x
5x = 42
x = 8.4
find y in the same way
you don't say if AP : PB = 2 : 3 or 3 : 2
I will assume the first. If otherwise it is very easy to change
If you make a sketch and draw the right-angled triangles, you can see ....
for the x:
(x-2)/(18-x) = 2/3
3x - 6 = 36 - 2x
5x = 42
x = 8.4
find y in the same way
Point A has coordinates A(1, 4) and point B has coordinates B(5, 1). Find the coordinates of the midpoint M of AB?
c3rfr3f3f34f4f3 is the odds of 6 so do whatevr
1 answer