200 mcg/mL protein x 0.10 mL = 20 mcg protein. You place that into a total volume of
0.10 mL + 0.90 mL + 2.00 mL so that 20 mcg is now in 3.00 mL (assuming the volumes are additive. Technically they are not but with such dilute solutions the difference is not enough to worry about.)
New concn protein is 20 mcg/3.00 mL = about 6.67 mcg/mL.
PLEASE HELP.
If I have 0.10 mL of 200 mcg/mL protein, 0.90 mL of distilled water, and 2.00 mL of Bradford reagent, what is the concentration of the protein?
2 answers
Thank you so much!