Please help ..i really cannot solve.

Question

1. x2y2-256=0
x2+256=(x+256)

Answer 1

x^2 y^2 = 256
xy = ±16
This a set of four hyperbolas with the axes as asymptotes

The 2nd equation
x^2 + 256 = x+256
x^2 - x = 0
x(x-1) = 0
x = 0,1

If you need a solution to both equations as a system, then x=0 is out (why)
so for x=1, y=±16