Let the vertices be A, B, and C, where A is the vertex opposite a(4,3) etc.
let's work on the x's first,
let the corresponding x's be p, q, and r
(p+q)/2 = 7
p + q = 14 -- #1
in the same way...
p + r = 10 -- #2
q + r = 8 -- #3
subtract #1 - #2
q - r = 4
add that to #3
2q = 12
q = 6
then r = 2
and p = 8
now do the y's the same way.
please help! i don't get these problems at all!
a(4,3) b(7,4) and c(5,2) are midpoints of a triangle. find the coordinates for the vertices of the triangle!
4 answers
wait what? I'm a bit confused here. so (4,3) would be on CB?
whats does corresponding x mean? and how did x appear?
whats does corresponding x mean? and how did x appear?
Yes, (4,3) is on CB
(5,2) on AB and (7,4) on AC
I let the points be A(p, ?), B(q, ?) and C(r, ?)
I then followed the definition of finding midpoints.
Don't you add up the x values , then divide by 2 , to get the x of the midpoint?
Pick your own values for the y's, and follow the same method.
(5,2) on AB and (7,4) on AC
I let the points be A(p, ?), B(q, ?) and C(r, ?)
I then followed the definition of finding midpoints.
Don't you add up the x values , then divide by 2 , to get the x of the midpoint?
Pick your own values for the y's, and follow the same method.
Sorry, but I got lost here...
I let the points be A(p, ?), B(q, ?) and C(r, ?)
^what does this?
I then followed the definition of finding midpoints.
Don't you add up the x values , then divide by 2 , to get the x of the midpoint?
I let the points be A(p, ?), B(q, ?) and C(r, ?)
^what does this?
I then followed the definition of finding midpoints.
Don't you add up the x values , then divide by 2 , to get the x of the midpoint?