No replacement (otherwise two identical poems)
Total=4+5+2+2=13 poems
5 Colerdge, 2 Byron
So
P(CB)=(5/13)*(2/12) =5/78
Please help. I didn't get the right answer with this question before:
Your English teacher has decided to randomly assign poems for the class to read. The syllabus includes 4 poems by Shakespeare, 5 poems by Coleridge, 2 poems by Tennyson, and 2 poems by Lord Byron. What is the probability that you will be assigned a poem by Coleridge and then a poem by Lord Byron?
Possible answers:
7/13, 9/13, 5/78, 6/13
1 answer