Ask a New Question
Menu

Please help I am stuck

evaluate the following intergral
x cos 15x dx.

1 answer

use integration by parts

u = x, du = dx
dv = cos 15x dx, v = 1/15 sin 15x

Now we have

∫x cos15x dx = 1/15 x sin15x - ∫1/15 sin15x dx

And that's clear sailing. . . right?
Similar Questions
  1. evaluate the intergral using substitutioningergral[(x^2-e^3x)/(x^3-e^3x)^2]dx
    1. answers icon 1 answer
    1. answers icon 0 answers
    1. answers icon 1 answer
  4. how do you evauste the intergralintergral (2x^4-2x^3+6x^2-5x+1)/(x^3-x^2+x-1)dx using partial fractions method?
    1. answers icon 1 answer
more similar questions