please help having trouble with this

(x+7)(x-12)(x+5)>0

the solution set is or is it all real numbers.

3 answers

All parts of the uneqiations must be large of 0

Less part is ( x - 12 )

Solution x > 12
multiply and simplify by factoring assume all expression under radicals represent non negative numbers

¡¼∛y¡½^7 ∛(¡¼81y¡½^8 )
knowing the general shape of a cubic, and knowing that the intercepts are
x = -7, 12 , and -5

we can see that
(x+7)(x-12)(x+5)>0

has solution -7 < x < -5 OR x > 12