Please help!!!!!!!!!!! Find all solutions in the interval [0,2π).

7. 2 sin^2x=sin x
Please answer asap

1 answer

2sin^2 x - sinx = 0
sinx(2sinx - 1) = 0
sinx = 0 or sinx = 1/2
x = 0,π, 2π
or
if sinx=1/2
x = π/6 or 5π/6