PLEASE HELP. DUE TOMORROW

Question

A large box 4.5 m on a
side has mass 90 kg. A force F
is applied as shown, making an
angle θ = 35
with respect to
the vertical. How large must
the force be to tip the box about
the pivot point P?

The force is being pulled downward with a 35 degree angle between the box and force. The pivot point is the bottom edge of the box that the force is pulling along.

Answer 1

F*sin(35) * 4.5=90*9.8*4.5/2

Then solve for F.

Answer 2

Thanks so much!