Neither do I. You haven't asked a question.
If you want dy/dt at (2,-3) then you just need to do
3y + 3x dy/dt - 6 + 4y dy/dt
but you can't evaluate anything, because you have no equation.
Why not try posting the entire question, not just part of it?
Please help don't understand how to solve it.
3xy-6x+2y^2
dx/dt=-6
x=2
y=-3
thank you
3 answers
Assume x and y are functions of t, Evaluate dy/dt,
3xy-6x+2y^2
dx/dt=-6
x=2
y=-3
dy/dt
3xy-6x+2y^2
dx/dt=-6
x=2
y=-3
dy/dt
Still no good, but let's assume you have
3xy-6x+2y^2 = 0
Then
3y dx/dt + 3x dy/dt - 6 dx/dt + 4y dy/dt = 0
(3x+4y) dy/dt = (6-3y) dx/dt
dy/dt = 3(2-y)(dx/dt)/(3x+4y)
dy/dt = 3(5)(-6)/(6-12) = 15
But that's so only if my original equation is close.
3xy-6x+2y^2 = 0
Then
3y dx/dt + 3x dy/dt - 6 dx/dt + 4y dy/dt = 0
(3x+4y) dy/dt = (6-3y) dx/dt
dy/dt = 3(2-y)(dx/dt)/(3x+4y)
dy/dt = 3(5)(-6)/(6-12) = 15
But that's so only if my original equation is close.
4 answers