(1/2) m v^2 = m g h
or use Bernoulli
(1/2) rho v^2 + rho g h + P = constant
here P = 1 atm on top of the tank and at the outflow so the two ways are the same
v = sqrt (2 g h ), just like the water fell
amount that comes out per second = Q = Area*v = pi r^2 v = pi*10^-4 v
so
Q = pi*10^-4* sqrt(2*9.81*8)
20 liters = .02 m^3 = Q t
so
t= .02/[pi*10^-4*sqrt(2*9.81*8)]
Please help! Any advice is appreciated
A water faucet in a house is h=8 m below the water surface in the local water tower. The
radius of the orifice in the fully opened faucet is r=0.01 m. We assume non-viscous flow
in this problem.
a) How long does it take to fill a 20 liter bucket with water using this faucet.
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