Please help and do it step by step all parts of questions and use:

Question

T = time(s)
I=current (amps)
Q=net charge on object (Coulombs)
N=no electrons (and write if added or removed from object and how)
E=elementary charge

Calculate the number of free electrons per metre length of wire if a current of 2.0A produces a drift velocity of 1.0 x 10^-3 ms-1.

As physics - bobpursley Tuesday, December 12, 2017 at 10:27am
current=driftevelocity*area*electrondensity

but number electrons per lenth=electron dinsity)*area

the equation i=anev
n=work out
i=2
a=???
v= 1.0 X 10^-3 ms-1
was what i thought at first but then 2 values were missing when only one should be then you said number "NUMBER electrons per lenth=electron dinsity)*area"

but i dont know the density of the electrons or the area pelase help

Answer 1

is there a way to work this out?

Answer 2

i cant find the numbers for the equation yo gave me
"NUMBER electrons per lenth=electron dinsity)*area"

Answer 3

an Ampere is a coulomb per sec

2 coulombs per sec
... 6.24E18 electrons per coulomb

drift velocity is ... 1.0E-3 m/s

so there are (2 * 6.24E18) free electrons in 1.0E-3 m of wire