there r 2 girls n one girl has $.60 more then the other and together they total $8.20. so u set up an equation
2x+.60=$8.20. u first subtract 60 cent from both sides n that leave u with 2x=$7.60. now u divide both sides by 2 to get how much each girl has n x= $3.80. n finally u add 60 cents to Beth's 3.80 n that gives u $4.40 for beth n $3.80 for suzy.
Please find the least common multiple for each set of numbers: 7,8,10 2,5,6 3,4,7
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Beth has $0.60 more than Suzy. Together they have $8.20. How much money does each girl have?
Thank you very much
4 answers
Are your sets?
7, 8, 10
2, 5, 6
3, 4, 7
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Let x = the money that Suzy has
x + x + 0.60 = 8.20
2x + 0.60 = 8.20
2x = 7.60
x = #3.80
7, 8, 10
2, 5, 6
3, 4, 7
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Let x = the money that Suzy has
x + x + 0.60 = 8.20
2x + 0.60 = 8.20
2x = 7.60
x = #3.80
This is just confusing a fifth grader. Do the easy way Jenny.
2 girls both together have $8.20.
Devide 8.20 by 2.
8.20/2= 4.10 one girl has .60 more than the other.
4.10-.30=3.80
one girl has $3.80 the other has $4.40.
$3.80+$4.40=$8.20
2 girls both together have $8.20.
Devide 8.20 by 2.
8.20/2= 4.10 one girl has .60 more than the other.
4.10-.30=3.80
one girl has $3.80 the other has $4.40.
$3.80+$4.40=$8.20
$8.80 you add