Please explain this to me

Question

2I- --> I2 + 2e
Cr2O72- ==> Cr3+

6e + 14H + Cr2O72- ==> 2Cr3+ + 7H20
I don't understand how the left side gets 6 electrons.

Answer 1

Cr on the left is +6 and there are two of them for a total of +12. On the right 2*+3 = +6. So both Cr atoms went from 12 on the left to 6 on the right which is a gain of 6e.

Answer 2

I can see that now thank you very much