Please check these:

1.When the fraction 2/3 is used as exponent, wht role does the denominator 3 play in evaluating expression? I think it indicates cube root of the base,correct?
2.sqrt of (2^4x/4^-2x) is equilvalent to 2^4x, correct?
3.Simplify (2xy^-2z^4/y^-3/z^3)^2 would be 4x^2y^2z^2,correct?
4. (4x^2y^-4z)^3 simplified would be 64x^6z^3/y^12, correct
Thank you

3 answers

1, correct
2. correct, good job on that one
3. not sure about the priority of the two divisions
I think the whole thing is squared, but you will need some additional brackets in that denominator
the way you typed it , it would be
[(2xy^-2 z^4) ( 1/y^-3) ( 1/z^3) ]^2 = 4x^2 y^2 z^2 which is your answer
OK then!

4. good again!
Thank you
what is the answer to this problem?

−x2+6zy=

x=10, y=−2, and z=−5.
Similar Questions
  1. Simplify using Exponent Rules: 74×7×713×7−20(1 point) Responses 28−2 28 to the negative 2 power 172 the fraction with
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. Simplify the expression using exponent properties.c12d3c11d5e−3 (1 point) Responses ce3d2 the fraction with numerator c e
    1. answers icon 1 answer
  3. Simplify x8x4(1 point) Responses Because the numerator has an exponent of 8 and the denominator has an exponent of 4, when you
    1. answers icon 1 answer
more similar questions