Nuts to your logic.
voltage in the parallel branch is due to the effective resistance of the parallel branch x total current.
effective resistance of parallel branch:
20 ohms, your work is correct there.
Total resistance: that 20 ohms in series with another 10, total 30 ohms.
total current: 180/30=6amps (note this is not what you did).
voltage on parallel branch: 20ohms*6amps 120 volts
current through 10 ohm: 6 amps.
Now your questions: what does a) mean? It makes no sense.
Please check my work here:
Resistors of 30 ohms and 60 ohms are connected in parallel and joined in series to a 10 ohm resistor.
The circuit voltage is 180 volts.
Find:
a)the voltage of the parallel circuit
b)the voltage across the parallel circuit
c)the current through the 10 ohm resistor
Ans: So for voltage of parallel circuit I took 180V/30 ohms = 6A. I multiplied that by 20 ohms that I had found by 1/r total = 1/30 + 1/60 = 20 ohms. So I got 120 V for voltage of the parallel circuit.
For voltage across the parallel circuit, I originally found 180V because I included the 60 V from the series. From what the tutors have said, this is the same problem as above one. Therefore, should my answer be 120 V instead of the 180V?
c) I used I = V/R = 60 V / 10 ohsm = 6 amps for the current through the 10 ohm resistor.
So I found: 120 V, 120 V again???, and 6A. Have I finally got it?
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