the domain is clearly not all real numbers.
Suppose x=0. No way can -9y^2 = 900
The hyperbola is
x^2/900 - y^2/100 = 1
The vertices of the hyperbola are at (±30,0)
So, the domain is (-∞,-30]U[30,∞)
Using what you know of the shape of hyperbolas, the range is clearly all real numbers.
Please Check My Answers!!!
What is the type of conic section is given by the equation x^2-9y^2=900 and what is
the domain and range?
Answer: Type is hyperbola, Domain is all real values of x, not sure what the range is. Please explain how to find these
What are the vertex, focus and directrix of a parabola with equation: x = y2 + 14y − 2
3 answers
As for the parabola, recall the properties of the parabola
y^2 = 4px
Yours is shifted a bit, making it
(y+7)^2 = 1(x+51)
y^2 = 4px
Yours is shifted a bit, making it
(y+7)^2 = 1(x+51)
How did you get the second one?? Also, thank you so much for the first answer. I realized what I was doing wrong lol. I knew how to do it, I was just doing it wrong today