Asked by Samantha
Please check for me.
7p - 7/p divided by 10p-10/5p^2
= 7p^2
6x - 6/x * 6x^2/8x-8
= 9x/2
I'm not sure how to answer this one.
x/2 divided by 9/x + 5
I think it's x(x + 5) / 18
Without grouping symbols () it is impossible to understand the problems.
The ^ means exponent and / is a fraction
(7p - 7/p) / (10p-10/5p^2)
= 7p^2
(6x - 6/x) * (6x^2/8x-8)
= 9x/2
I'm not sure how to answer this one.
(x/2) / (9/x + 5)
I think it's x(x + 5) / 18
For your first one:
(7p - 7/p) / (10p-10/5p^2)
Let's find common denominators and try to simplify from there.
Using p as a common denominator in the numerator, we have this:
(7p^2/p - 7/p) / [ 10(p - 1)/5p^2) ]
Going from there, we have:
[ (7p^2 - 7)/p ] / [ 2(p - 1)/p^2 ]
[ 7(p^2 - 1)/p ] / [ 2(p - 1)/p^2 ]
[ 7(p + 1)(p - 1)/p ] * [ p^2/2(p - 1) ]
Cancel out common terms in the numerator and denominator of the fractions.
When you do this, you will end up with:
7p(p + 1)/2
And that's as far as we can go on this one.
For your second problem:
(6x - 6/x) * (6x^2/8x-8)
(6x^2/x - 6/x) * [ 6x^2/8(x - 1) ]
(6x^2 - 6)/x * [ 6x^2/8(x - 1) ]
[ 6(x^2 - 1)/x ] * [ 6x^2/8(x - 1) ]
[ 6(x + 1)(x - 1)/x ] * [ 6x^2/8(x - 1) ]
Cancel out like terms and reduce where you can to end up with this:
9x(x + 1)/2
And that's as far as we can go on this one.
For your final problem:
(x/2) / [ 9/(x + 5) ]
Your answer is correct!
I hope this helps.
7p - 7/p divided by 10p-10/5p^2
= 7p^2
6x - 6/x * 6x^2/8x-8
= 9x/2
I'm not sure how to answer this one.
x/2 divided by 9/x + 5
I think it's x(x + 5) / 18
Without grouping symbols () it is impossible to understand the problems.
The ^ means exponent and / is a fraction
(7p - 7/p) / (10p-10/5p^2)
= 7p^2
(6x - 6/x) * (6x^2/8x-8)
= 9x/2
I'm not sure how to answer this one.
(x/2) / (9/x + 5)
I think it's x(x + 5) / 18
For your first one:
(7p - 7/p) / (10p-10/5p^2)
Let's find common denominators and try to simplify from there.
Using p as a common denominator in the numerator, we have this:
(7p^2/p - 7/p) / [ 10(p - 1)/5p^2) ]
Going from there, we have:
[ (7p^2 - 7)/p ] / [ 2(p - 1)/p^2 ]
[ 7(p^2 - 1)/p ] / [ 2(p - 1)/p^2 ]
[ 7(p + 1)(p - 1)/p ] * [ p^2/2(p - 1) ]
Cancel out common terms in the numerator and denominator of the fractions.
When you do this, you will end up with:
7p(p + 1)/2
And that's as far as we can go on this one.
For your second problem:
(6x - 6/x) * (6x^2/8x-8)
(6x^2/x - 6/x) * [ 6x^2/8(x - 1) ]
(6x^2 - 6)/x * [ 6x^2/8(x - 1) ]
[ 6(x^2 - 1)/x ] * [ 6x^2/8(x - 1) ]
[ 6(x + 1)(x - 1)/x ] * [ 6x^2/8(x - 1) ]
Cancel out like terms and reduce where you can to end up with this:
9x(x + 1)/2
And that's as far as we can go on this one.
For your final problem:
(x/2) / [ 9/(x + 5) ]
Your answer is correct!
I hope this helps.
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