v=at so velocity is increasing linearly. So at time 1, v=5a, distance=v*t=25a
at time 2, v=10a, and distance=100a
so the distance is 4x as far, so the sound diminished as the square of the diatnace, so intensity is 1/16..
Please can anyone explain. Thank you.
A rocket is launched vertically from ground with a constant acceleration. If the rocket emits a burst of sound every five seconds after launching, find the difference of intensity levels observed at the launching site for the first and the second bursts of sound.
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