The equation for the surface area of the triangular pyramid net shown in the image is:
SA = (1/2 * base * height) + (1/2 * perimeter * slant height)
SA = (1/2 * 17 * 14.72) + (1/2 * (11 * 3) * 10.99)
SA = (8.5 * 14.72) + (5.5 * 3 * 10.99)
SA = 125.2 + 181
SA = 306.2 square millimeters.
PLEASE answer correctly and use the details i give you to answer the question.
An illustration of a triangular pyramid net shows an inverted equilateral triangle as the base, with sides measuring 17 millimeters. Three identical isosceles triangles extend from each side of the base. A dashed line bisects the central inverted triangle and is labeled as h equals 14.72 millimeters. The outer edges of the three isosceles triangles joined to the 17 millimeter base are all labeled as 11 millimeters. A dashed line bisects the outer triangle on the left and is labeled as h equals 10.99 millimeters.
Write the equation for the surface area of the triangular pyramid net shown in the image. Remember, SA=(1/2base⋅height)+(1/2perimeter⋅slant height)
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