Playing jackstone as a kid, you discovered that there is a certain time before the rubber ball falls and you took advantage of this when picking up the stars on the floor. If you threw the ball (5.17)m/s up into the air, how fast will it be moving at a height of (61.70)cm? How much time has elapsed upon reaching this height?
2 answers
see related questions below.
1. V^2 = Vo^2+2g*h = 5.17^2+(-19.6)0.617 = 14.64
V = 3.8 m/s.
2. V = Vo+g*T = 3.8
5.17-9.8T = 3.8
T =
V = 3.8 m/s.
2. V = Vo+g*T = 3.8
5.17-9.8T = 3.8
T =
3 answers