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Original Question
place the numbers in descending order. 2.3 x 10^-10; 3.2 x 10^-10; 23 x 10^-12; 2.3 x 10^-8Question
Place the numbers in descending order.
2.3 x 10^-8
2.3 x 10-10
2.3 x 10^-12
2.3 x 10^-10
2.3 x 10^-8
2.3 x 10-10
2.3 x 10^-12
2.3 x 10^-10
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Answered by
GPT-4o mini
To place the numbers in descending order, we need to first express them clearly and then compare their values based on the exponent part:
1. \( 2.3 \times 10^{-8} \)
2. \( 2.3 \times 10^{-10} \) (first instance)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-10} \) (second instance)
Now, we compare the exponents:
- \( 10^{-8} \) is greater than \( 10^{-10} \) and \( 10^{-12} \).
- \( 10^{-10} \) is greater than \( 10^{-12} \).
Thus, the order from greatest to least is:
1. \( 2.3 \times 10^{-8} \)
2. \( 2.3 \times 10^{-10} \) (first instance)
3. \( 2.3 \times 10^{-10} \) (second instance)
4. \( 2.3 \times 10^{-12} \)
In conclusion, the numbers in descending order are:
\( 2.3 \times 10^{-8}, 2.3 \times 10^{-10}, 2.3 \times 10^{-10}, 2.3 \times 10^{-12} \)
1. \( 2.3 \times 10^{-8} \)
2. \( 2.3 \times 10^{-10} \) (first instance)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-10} \) (second instance)
Now, we compare the exponents:
- \( 10^{-8} \) is greater than \( 10^{-10} \) and \( 10^{-12} \).
- \( 10^{-10} \) is greater than \( 10^{-12} \).
Thus, the order from greatest to least is:
1. \( 2.3 \times 10^{-8} \)
2. \( 2.3 \times 10^{-10} \) (first instance)
3. \( 2.3 \times 10^{-10} \) (second instance)
4. \( 2.3 \times 10^{-12} \)
In conclusion, the numbers in descending order are:
\( 2.3 \times 10^{-8}, 2.3 \times 10^{-10}, 2.3 \times 10^{-10}, 2.3 \times 10^{-12} \)
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