Question

Place the numbers in descending order:

2.3 x 10^-10 ; 3.2 x 10^-10 ; 2.3 x 10^-12 ; 2.3 x 10^-8

Answer 1

are you sure

Answer 2

To arrange the numbers in descending order, we first need to express them in decimal form for easy comparison.

1. \(2.3 \times 10^{-10} = 0.00000000023\)
2. \(3.2 \times 10^{-10} = 0.00000000032\)
3. \(2.3 \times 10^{-12} = 0.0000000000023\)
4. \(2.3 \times 10^{-8} = 0.000000023\)

Now we can compare:

- \(2.3 \times 10^{-8} = 0.000000023\)
- \(2.3 \times 10^{-10} = 0.00000000023\)
- \(3.2 \times 10^{-10} = 0.00000000032\)
- \(2.3 \times 10^{-12} = 0.0000000000023\)

Arranging these from largest to smallest gives:

1. \(2.3 \times 10^{-8}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\)

Therefore, the numbers in descending order are:

\[ 2.3 \times 10^{-8}, 3.2 \times 10^{-10}, 2.3 \times 10^{-10}, 2.3 \times 10^{-12} \]

Answer 3

Let me double-check the calculations for the numbers in descending order:

1. **Convert to decimal:**
- \(2.3 \times 10^{-10} = 0.00000000023\)
- \(3.2 \times 10^{-10} = 0.00000000032\)
- \(2.3 \times 10^{-12} = 0.0000000000023\)
- \(2.3 \times 10^{-8} = 0.000000023\)

2. **Arranging the decimals:**
- \(2.3 \times 10^{-8} = 0.000000023\)
- \(3.2 \times 10^{-10} = 0.00000000032\)
- \(2.3 \times 10^{-10} = 0.00000000023\)
- \(2.3 \times 10^{-12} = 0.0000000000023\)

3. **Order by magnitude:**
- The largest value is \(2.3 \times 10^{-8}\).
- The second largest is \(3.2 \times 10^{-10}\).
- The third is \(2.3 \times 10^{-10}\).
- The smallest is \(2.3 \times 10^{-12}\).

Thus, I confirm that the correct order from largest to smallest is:

1. \(2.3 \times 10^{-8}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\)

Thank you for your patience!