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Place the numbers in descending order. 2.3 * 10 ^ - 10 3.2 * 10 ^ - 10 2.3 * 10 ^ - 12 2.3 * 10 ^ - 8Asked by woosan♥
Place the numbers in descending order.
2.3 × 10−10
; 3.2 × 10−10
; 2.3 × 10−12
; 2.3 × 10−8
2.3 × 10−10
; 3.2 × 10−10
; 2.3 × 10−12
; 2.3 × 10−8
Answers
Answered by
GPT-4o mini
To place the numbers in descending order, we can first convert them into decimal form for easier comparison. Here are the numbers converted:
1. \(2.3 \times 10^{-10} = 0.00000000023\)
2. \(3.2 \times 10^{-10} = 0.00000000032\)
3. \(2.3 \times 10^{-12} = 0.0000000000023\)
4. \(2.3 \times 10^{-8} = 0.000000023\)
Now, we can compare the decimal values:
- \( 2.3 \times 10^{-8} = 0.000000023 \)
- \( 3.2 \times 10^{-10} = 0.00000000032 \)
- \( 2.3 \times 10^{-10} = 0.00000000023 \)
- \( 2.3 \times 10^{-12} = 0.0000000000023 \)
Now, arranging them in descending order:
1. \(2.3 \times 10^{-8}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\)
So, the final order in descending format is:
**2.3 × 10^{-8}; 3.2 × 10^{-10}; 2.3 × 10^{-10}; 2.3 × 10^{-12}**
1. \(2.3 \times 10^{-10} = 0.00000000023\)
2. \(3.2 \times 10^{-10} = 0.00000000032\)
3. \(2.3 \times 10^{-12} = 0.0000000000023\)
4. \(2.3 \times 10^{-8} = 0.000000023\)
Now, we can compare the decimal values:
- \( 2.3 \times 10^{-8} = 0.000000023 \)
- \( 3.2 \times 10^{-10} = 0.00000000032 \)
- \( 2.3 \times 10^{-10} = 0.00000000023 \)
- \( 2.3 \times 10^{-12} = 0.0000000000023 \)
Now, arranging them in descending order:
1. \(2.3 \times 10^{-8}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\)
So, the final order in descending format is:
**2.3 × 10^{-8}; 3.2 × 10^{-10}; 2.3 × 10^{-10}; 2.3 × 10^{-12}**
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