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Original Question
Place the numbers in descending order. 2.3 * 10 ^ - 10 3.2 * 10 ^ - 10 2.3 * 10 ^ - 12 2.3 * 10 ^ - 8Question
Place the numbers in descending order.
2.3 × 10−10 ; 3.2 × 10−10 ; 2.3 × 10−12 ; 2.3 × 10−8
2.3 × 10−10 ; 3.2 × 10−10 ; 2.3 × 10−12 ; 2.3 × 10−8
Answers
Answered by
GPT-4o mini
To place the numbers in descending order, we first need to compare them by their exponents. The larger the exponent in a scientific notation, the larger the number.
Here are the numbers you provided:
1. \( 2.3 \times 10^{-10} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-8} \)
Now, let's compare them:
- \( 2.3 \times 10^{-8} \) has the largest exponent (-8), so it is the largest number.
- Next, we compare \( 2.3 \times 10^{-10} \) and \( 3.2 \times 10^{-10} \). Since \( 3.2 \) is greater than \( 2.3 \) but both have the same exponent (-10), \( 3.2 \times 10^{-10} \) is the next largest.
- \( 2.3 \times 10^{-10} \) comes next.
- Finally, \( 2.3 \times 10^{-12} \) has the smallest exponent (-12), so it is the smallest number.
Putting this together, the numbers in descending order are:
1. \( 2.3 \times 10^{-8} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \)
Here are the numbers you provided:
1. \( 2.3 \times 10^{-10} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-8} \)
Now, let's compare them:
- \( 2.3 \times 10^{-8} \) has the largest exponent (-8), so it is the largest number.
- Next, we compare \( 2.3 \times 10^{-10} \) and \( 3.2 \times 10^{-10} \). Since \( 3.2 \) is greater than \( 2.3 \) but both have the same exponent (-10), \( 3.2 \times 10^{-10} \) is the next largest.
- \( 2.3 \times 10^{-10} \) comes next.
- Finally, \( 2.3 \times 10^{-12} \) has the smallest exponent (-12), so it is the smallest number.
Putting this together, the numbers in descending order are:
1. \( 2.3 \times 10^{-8} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \)
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