Question

Place the numbers in descending order.

2.3 × 10−10
; 3.2 × 10−10
; 2.3 × 10−12
; 2.3 × 10−8

Answer 1

To compare the numbers, we can convert them to a common format or compare their values directly based on the power of ten.

Here are the numbers:

1. \( 2.3 \times 10^{-10} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-8} \)

Now, we can compare:

- \( 2.3 \times 10^{-8} \) is the largest because it has the highest power of ten.
- Next are \( 2.3 \times 10^{-10} \) and \( 3.2 \times 10^{-10} \). Between these, \( 3.2 \times 10^{-10} \) is larger.
- Finally, \( 2.3 \times 10^{-12} \) is the smallest.

Putting them in descending order:

1. \( 2.3 \times 10^{-8} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \)

Thus, the final order is:

**2.3 × 10−8, 3.2 × 10−10, 2.3 × 10−10, 2.3 × 10−12**.