a. -2.0, -1.02, 0.25, 1.98
b. 0.25, -1.02, 1.98, -2.0
c. -1.02, -2.0, 0.25, 1.98
d. 1.98, 0.25, -1.02, -2.0
9 answers
To place the numbers -2.0, 0.25, -1.02, and 1.98 on a number line from left to right, we need to arrange them in ascending order.
The correct order is: -2.0 (the smallest) -1.02 (less than 0 but greater than -2) 0.25 (greater than 0, but less than 1) 1.98 (the largest)
So the order from left to right is:
-2.0, -1.02, 0.25, 1.98
The correct answer is a. -2.0, -1.02, 0.25, 1.98.
To find the sum of \( p \) and \( q \):
\[ p = \frac{3}{4} \] \[ q = \frac{11}{4} \]
Now, add the two fractions:
\[ p + q = \frac{3}{4} + \frac{11}{4} \]
Since they have the same denominator, we can add the numerators directly:
\[ = \frac{3 + 11}{4} \] \[ = \frac{14}{4} \]
Now, reduce \( \frac{14}{4} \) to lowest terms. Both the numerator and denominator can be divided by 2:
\[ = \frac{14 \div 2}{4 \div 2} = \frac{7}{2} \]
Thus, the sum of \( p \) and \( q \) is:
\[ \frac{7}{2} \]
To find the sum of \( p \) and \( q \):
Given: \[ p = \frac{3}{4} \] \[ q = \frac{11}{4} \]
Now, add the two fractions:
\[ p + q = \frac{3}{4} + \frac{11}{4} \]
Since they have the same denominator, we can simply add the numerators:
\[ = \frac{3 + 11}{4} \] \[ = \frac{14}{4} \]
Now, reduce \( \frac{14}{4} \) to its lowest terms. Both the numerator and denominator can be divided by 2:
\[ = \frac{14 \div 2}{4 \div 2} = \frac{7}{2} \]
Thus, the sum of \( p \) and \( q \) is:
\[ \frac{7}{2} \]
The sum of \( p \) and \( q \) is:
\[ \frac{7}{2} \]
To express this as a decimal, divide 7 by 2:
\[ \frac{7}{2} = 3.5 \]
So, the answer is:
3.5
To find the current temperature after a change of -18.6°C from 13°C, you simply subtract the temperature change from the initial temperature:
\[ \text{Current Temperature} = 13°C + (-18.6°C) \]
This simplifies to:
\[ \text{Current Temperature} = 13°C - 18.6°C = -5.6°C \]
Thus, the current temperature is -5.6°C.
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