Ask a New Question
Menu

Piecewise function problem.

Let f(x)={ax^2+1/3, x is greater than or equal to 1; bx-10/3, x<1. If the function is differentiable, find the sum of a+b.

1 answer

f(x) =
ax^2 + 1/3 for x >= 1
bx - 10/3 for x < 1

so, we need f(1) to be consistent. That is,

a + 1/3 = b - 10/3

we also need f'(1) to be consistent:

2a = b

so, a + 1/3 = 2a - 10/3
a = 11/3
b = 22/3

a+b = 11
Similar Questions
  1. the absolute value functiong(x) = |5-x| can be written as a piecewise function. the piecewise function which represents g(x) is
    1. answers icon 3 answers
  2. Let f be the function defined by the piecewise function:f(x) = x^3 for x less than or equal to 0 x for x greater than 0 Which of
    1. answers icon 2 answers
  3. I am doing the piecewise function x+3 if x is less than -2x^2 if -2 is less than or equal to x which is less than 1, and
    1. answers icon 0 answers
  4. I have the question y=-|x^2 -9|I am asked for the piecewise function. I have written y={-x^2 +9 if x less than equal to -3} {
    1. answers icon 1 answer
more similar questions