Picture of a 6 inch cake by 9 inch rectangular cake that is 2 inches tall if you cover the cake with frosting, excluding the bottom what is the surface area of the cake that would be covered with frosting?

Answer 1

The top of the cake has dimensions of 6 inches by 9 inches, which is 54 square inches. The sides of the cake have an area of (2 x 6) + (2 x 9) x 2 = 60 square inches. Therefore, the total surface area of the cake that would be covered with frosting is 54 + 60 = 114 square inches.