Philip is sorting of acorns he collected he has 92 acorns 66 still have their tops 26 do not Philip wants to sort the acorns into groups with the same number of acorns including some with without tops he wants each group to have an equal number of acorns with tops and equal number of acorns without tops which answer best shows how Philip can represent how we should sort the acorns A 1 (66 + 26) B 24 (3 + 1) C 2 (33 + 13) D 6 (11 + 4)

Answer 1

To solve the problem, we need to find a way to sort the acorns into groups where each group has the same number of acorns with tops and the same number of acorns without tops.

Philip has:

• 66 acorns with tops
• 26 acorns without tops

Total = 66 + 26 = 92 acorns.

To represent the groups correctly, we need the number of groups to be a divisor of both 66 and 26 so that each group can have an equal number of acorns of each type.

Let’s examine each option:

A: 1 (66 + 26)

• This option implies one group with all acorns, which doesn't satisfy the requirement for equal groups of with and without tops.

B: 24 (3 + 1)

• 24 is not a divisor of either 66 or 26, thus not a suitable grouping.

C: 2 (33 + 13)

• 2 is a divisor of 66 and 26 (as 66 / 2 = 33 and 26 / 2 = 13). This indicates that Philip can sort the acorns into 2 groups, where each group has 33 with tops and 13 without tops. This option works.

D: 6 (11 + 4)

• 6 is not a divisor of 66, therefore it doesn’t work for sorting.

The best representation of how Philip can sort the acorns is represented by:

C: 2 (33 + 13)

This means he can create 2 groups, with each group having 33 acorns with tops and 13 acorns without tops.