ph of 350 mL of a solution that contains 2.64x10-2 mol H+

Answer 1

To calculate the pH of the solution, we first need to calculate the concentration of H+ ions in the solution.

The concentration of H+ ions is 2.64x10-2 mol in 350 mL of solution. We first convert the volume to liters:

350 mL = 0.35 L

Now we calculate the concentration of H+ ions in mol/L:

[ H+ ] = (2.64x10-2 mol) / 0.35 L
= 7.54x10-2 mol/L

Now we can calculate the pH using the formula:

pH = -log [H+]

pH = -log (7.54x10-2)
pH ≈ -log (7.54) = -(-1.12) = 1.12

Therefore, the pH of the solution is approximately 1.12.