Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child? (5 points)

Question

4 over 12 plus 3 over 12 is equal to 7 over 12

4 over 12 plus 3 over 11 is equal to 80 over 132

4 over 12 multiplied by 3 over 12 is equal to 12 over 144

4 over 12 multiplied by 3 over 11 is equal to 12 over 132

Answer 1

The correct calculation is:
4/12 (probability of selecting a blue marble for the first child) * 3/11 (probability of selecting a yellow marble for the second child) = 12/132 = 1/11

Therefore, the probability that Peter will give a blue marble to the first child and then a yellow marble to the second child is 1/11.