Pertaining to the previous question, if two of the vertices of a feasible region are at (1,3) and (6,1) how would the linear equation representing a line connecting them be found?

Answer 1

y=m x + b
where m=(3-1)/(1-6)=-2/5 check that.

y=-2/5 x + b now put in either point..
3=-2/5 (1)+b
b=3+2/5
so y=-2/5 x + 3+2/5

Answer 2

Thanks, I appreciate the help.