Person A walks 6.0 m at an angle of 30 north of east. Person B walks 7.0 m at an angle of 42 west of north. How does the component of the displacement of person A along the north direction compare with the component of the displacement of person B along the north direction?

Question

A.
It is larger.
B.
It is smaller.
C.
They are equal.
D.
There is not sufficient information to tell.

Answer 1

A = 6m[30o[
Y = 6*sin30 = 3m = North Component.

B = 7m[132o], CCW.
Y = 7*sin132 = 5,20 m. = North component.

The component along the north direction
of person A is smaller.