-2x+y=7 can be written as
y=2x+7, so we see it has slope=2
so, the perpendicular has slope -1/2
now you have a point and a slope:
y+2 = -1/2 (x+4)
and you can massage that as you will.
perpendicular to line -2x+y=7 contains the point (-4,-2) the equation of line is
2 answers
6x+2y=12
find intercept
a circle equation x^2+y^2+4x-4y-1=0 and graph
2)find domain and range f(x)=x^2-4x-5
find vertex of f(x) =x^2+4x-21
find intercept
a circle equation x^2+y^2+4x-4y-1=0 and graph
2)find domain and range f(x)=x^2-4x-5
find vertex of f(x) =x^2+4x-21